1. A train starts from station A and reaches B 15 minutes late when it moves with 40 km/hr and 24 minutes late when it goes 30 km/hr. The distance between the two stations is
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By: anil on 05 May 2019 01.51 am
Let the distance between the two stations be $$d$$ km and time taken be $$t$$ hours.
When it moves with 40 km/hr, it reaches 15 mins late, so total time taken is => $$frac{d}{40} = t + frac{15}{60}$$ --------Eqn(1) Similarly, => $$frac{d}{30} = t + frac{24}{60}$$ -----------Eqn(2) Subtracting eqn(1) from (2), we get :
=> $$frac{d}{30}-frac{d}{40} = frac{9}{60}$$ => $$frac{d}{120} = frac{9}{60}$$ => $$d$$ = 9*2 = 18 km
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When it moves with 40 km/hr, it reaches 15 mins late, so total time taken is => $$frac{d}{40} = t + frac{15}{60}$$ --------Eqn(1) Similarly, => $$frac{d}{30} = t + frac{24}{60}$$ -----------Eqn(2) Subtracting eqn(1) from (2), we get :
=> $$frac{d}{30}-frac{d}{40} = frac{9}{60}$$ => $$frac{d}{120} = frac{9}{60}$$ => $$d$$ = 9*2 = 18 km