1. A train travels 500 m in first minute. In the next 4 minutes, it travels in each minute 125 m more than that in the previous minute. The average speed per hour of the train during those 5 minutes will be
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By: anil on 05 May 2019 01.51 am
Distance travelled by the train in the first minute = 500m In the second minute = 500+125 = 625m In the third minute = 625+125 = 750m Similarly in the 4th and 5th minutes distance travelled will be 875m and 1000m respectively. Total distance travelled = 500+625+750+875+1000 = 3750m = 3.75 km Total time taken = 5 min = $$frac{1}{12}$$ hour Average speed = $$frac{3.75}{frac{1}{12}}$$ = 3.75 * 12 = 45 kmph
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