1. The perimeters of a square and a rectangle are equal . If their area be 'A' m2 and 'B' m2 then correct statement is
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By: anil on 05 May 2019 01.50 am
Let side of square = $$s$$ and length and breadth of rectangle be $$l$$ and $$b$$ respectively. According to ques, Perimeter of square = Perimeter of rectangle => $$4s=2(l+b)$$ => $$2s=l+b$$ Thus, $$l,s,b$$ are in A.P. and $$s^2$$ > $$lb$$ For example : $$4,6,8$$ where $$6^2$$ > $$4 imes8$$ Thus, A > B => Ans - (C)
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