1. Radius of cross section of a solid right circular cylindrical rod is 3.2 dm. The rod is melted and 44 equal solid cubes of side 8 cm are formed. The length of the rod is (Take Π = 22/7)





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  • By: anil on 05 May 2019 01.48 am
    Let length of cylindrical rod = $$h$$ cm and radius = $$r$$ = 3.2 dm = 32 cm Edge of cube = $$a=8$$ cm Volume of cylindrical rod = $$44 imes $$ Volume of cube => $$pi r^2 h= 44 imes a^3$$ => $$frac{22}{7} imes (32)^2 h = 44 imes (8)^3$$ => $$(32)^2 h=44 imes (8)^3 imes frac{7}{22}$$ => $$h=frac{14 imes (8)^3}{(32)^2}$$ => $$h=frac{14}{2}=7$$ cm => Ans - (B)
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