1. The perimeter of an isosceles triangle is 32 cm and each of the equal sides is 5/6 times of the base. What is the area $$(in cm^{2})$$ of the triangle ?
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By: anil on 05 May 2019 01.48 am
Given $$S = frac{5}{6} imes x$$
perimeter = 32 s + s + x = 32 2s + x = 32 2(5/6)x + x = 32 x = 12, s = 10. let h be the height of the triangle, $$h=sqrt{s^{2}-(a/2)^{2}}$$ = $$8$$ area of triangle = $$frac{1}{2} imes bh$$ = $$frac{1}{2} imes 12 imes 8= 48$$ so the answer is option B.
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perimeter = 32 s + s + x = 32 2s + x = 32 2(5/6)x + x = 32 x = 12, s = 10. let h be the height of the triangle, $$h=sqrt{s^{2}-(a/2)^{2}}$$ = $$8$$ area of triangle = $$frac{1}{2} imes bh$$ = $$frac{1}{2} imes 12 imes 8= 48$$ so the answer is option B.