1. In triangle ABC, a line is drawn from the vertex A to a point D on BC. If BC = 9 cm and DC = 3 cm, then what is the ratio of the areas of triangle ABD and triangle ADC respectively?





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  • By: anil on 05 May 2019 01.48 am
    Given : BC = 9 cm and DC = 3 cm and AE = $$h$$ cm => BD = 9-3 = 6 cm Now, area of $$ riangle$$ ABD = $$frac{1}{2} imes(BD) imes(AE)$$ = $$frac{1}{2} imes6 imes h=3h$$ $$cm^2$$ Similarly, area of $$ riangle$$ ADC = = $$frac{1}{2} imes3 imes h=1.5h$$ $$cm^2$$ $$ herefore$$ Required ratio = $$frac{3h}{1.5h}=frac{2}{1}$$ => Ans - (B)
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