1. A train leaves Delhi at 10 a.m. and reaches Jaipur at 4 p.m. on same day. Another train leaves Jaipur at 12 p.m. and reaches Delhi at 5 p.m. on same day. What is the time of day (approximately) when the two trains will meet?





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  • By: anil on 05 May 2019 01.48 am
    Total time taken by first train = 6 hours and second train = 5 hours $$ecause speed proptofrac{1}{time}$$ => Let speed of first train = $$5x$$ km/hr and speed of second train = $$6x$$ km/hr => Distance between Delhi and Jaipur = $$5x imes6=30x$$ km At 10:00 am, first train starts moving, => distance covered by it in 2 (12-10) hours = $$5x imes2=10x$$ km Distance left between the two trains at 12:00 pm = $$30x-10x=20x$$ km Now, at 12:00 pm both move towards each other, => relative speed = $$5x+6x=11x$$ km/hr => Time taken to meet each other = $$(frac{20x}{11x} imes60)$$ minutes $$approx 109$$ minutes = 1 hour and 49 minutes $$ herefore$$ Time at which they will meet = 12:00 pm + 1 hour and 49 minutes = 1:49 pm => Ans - (D)
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