1. Smaller diagonal of a rhombus is equal to length of its sides. If length of each side is 6 cm, then what is the area $$(in cm^2)$$ of an equilateral triangle whose side is equal to the bigger diagonal of the rhombus?
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By: anil on 05 May 2019 01.48 am
Let bigger diagonal of rhombus = BD = $$2x$$ cm and smaller diagonal = AC = 6 cm
Diagonals of a rhombus bisect each other at right angle. => OC = 3 cm and OD = $$x$$ cm In $$ riangle$$ OCD, => $$(OD)^2=(CD)^2-(OC)^2$$ => $$(OD)^2=(6)^2-(3)^2$$ => $$(OD)^2=36-9=27$$ => $$OD=sqrt{27}=3sqrt3$$ cm Thus, side of equilateral triangle = bigger diagonal = $$2 imes3sqrt3=6sqrt3$$ cm $$ herefore$$ Area of equilateral triangle = $$frac{sqrt3}{4}a^2$$ = $$frac{sqrt3}{4} imes(6sqrt3)^2$$ = $$frac{sqrt3}{4} imes108=27sqrt3$$ $$cm^2$$ => Ans - (B)
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Diagonals of a rhombus bisect each other at right angle. => OC = 3 cm and OD = $$x$$ cm In $$ riangle$$ OCD, => $$(OD)^2=(CD)^2-(OC)^2$$ => $$(OD)^2=(6)^2-(3)^2$$ => $$(OD)^2=36-9=27$$ => $$OD=sqrt{27}=3sqrt3$$ cm Thus, side of equilateral triangle = bigger diagonal = $$2 imes3sqrt3=6sqrt3$$ cm $$ herefore$$ Area of equilateral triangle = $$frac{sqrt3}{4}a^2$$ = $$frac{sqrt3}{4} imes(6sqrt3)^2$$ = $$frac{sqrt3}{4} imes108=27sqrt3$$ $$cm^2$$ => Ans - (B)