1. If the radius of the cylinder is increased by 25%, then by how much percent the height must be reduced, so that the volume of the cylinder remains same?
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By: anil on 05 May 2019 01.47 am
Let radius of cylinder = 10 cm and height = 10 cm => Volume = $$pi r^2h$$ = $$pi (10)^2 imes10=1000pi$$ If radius is increased by 25%, => new radius = $$frac{125}{100} imes10=12.5$$ cm => $$pi r^2h=1000pi$$ => $$(12.5)^2h=1000$$ => $$h=frac{1000}{156.25}=6.4$$ $$ herefore$$ Decrease in height = $$frac{(10-6.4)}{10} imes100$$ = $$3.6 imes10=36\%$$ => Ans - (A)
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