1. By what least number should 1200 be multiplied so that it becomes a perfect square?
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By: anil on 05 May 2019 01.47 am
Prime factorization of 1200 = $$2^4 imes3 imes5^2$$ Now, to make it a perfect square, all the powers should be even, but clearly power of 3 is 1, which is odd. Thus, least number that should be multiplied by 1200 so that it becomes a perfect square = 3 => $$1200 imes3=3600=(60)^2$$ => Ans - (B)
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