1. ABC is an equilateral triangle and P is the orthocenter of the triangle, then what is the value (in degrees) of ∠BPC?
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By: anil on 05 May 2019 01.46 am
Given : ABC is an equilateral triangle and P is the orthocenter
To find : $$angle BPC = ?$$ Solution : ABC is an equilateral triangle and thus $$angle A=60^circ$$ Also, $$angle BPC = 90^circ+frac{angle A}{2}$$ = $$90+frac{60}{2}$$ = $$90+30=120^circ$$ => Ans - (B)
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To find : $$angle BPC = ?$$ Solution : ABC is an equilateral triangle and thus $$angle A=60^circ$$ Also, $$angle BPC = 90^circ+frac{angle A}{2}$$ = $$90+frac{60}{2}$$ = $$90+30=120^circ$$ => Ans - (B)