1. Price of a diamond is directly proportional to square of its weight. A man broke the diamond accidentally in three pieces in the ratio of 3 : 5 : 7 and thus loses Rs 42600. What was the original price (in Rs) of the diamond?
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By: anil on 05 May 2019 01.46 am
Let weight of original diamond = $$15x$$ and price of diamond = Rs. $$C$$ According to ques, => $$C propto (15x)^2$$ => $$C=225kx^2$$ --------------(i) Let weight of each broken piece be $$3x,5x$$ and $$7x$$ g Thus, cost of first piece (from equation (i)) = $$k(3x)^2=9kx^2$$ Similarly, price of each of the remaining pieces = $$25kx^2$$ and $$49kx^2$$ => Total cost = $$9kx^2+25kx^2+49kx^2= 83kx^2$$ Amount lost = $$225kx^2-83kx^2=42600$$ => $$kx^2=frac{42600}{142}=300$$ $$ herefore$$ Original price of diamond = $$225 imes300=Rs.$$ $$67,500$$ => Ans - (C)
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