Let the first term of an AP = $$a$$ and the common difference = $$d$$ 3th term of AP = $$A_3=a+2d=-13$$ ----------(i) 8th term = $$A_8=a+7d=2$$ --------(ii) Subtracting equation (i) from (ii), we get : => $$7d-2d=2-(-13)$$ => $$5d=15$$ => $$d=frac{15}{5}=3$$ Substituting it in equation (ii), => $$a=2-7(3)=2-21=-19$$ $$ herefore$$ 14th term = $$A_{14}=a+13d$$ = $$-19+13(3)=-19+39=20$$ => Ans - (C)