1. D and E are points on side AB and AC of ΔABC. DE is parallel to BC. If AD:DB = 2:3, what is the ratio of area of ΔADE and area of quadrilateral BDEC?
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By: anil on 05 May 2019 01.44 am
ADE & ABC are similar, let area of $$ riangle$$ ABC = y, that of ADE = x For similar triangles Ratio of sides = $$sqrt{ ext(ratio of areas)}$$ AB/AD = $$sqrt{ frac{area.ABC}{area.ADE}}$$ 5/2 = $$sqrt{ frac{y}{x}}$$ 25/4 = $$frac{y}{x}$$ y = 25x/4 area of quadrilateral BDEC = ABC - ADE = y - x = 25x/4 - x = 21x/4
$$frac{ADE}{BDEC} = frac{x}{21x/4} = frac{4x}{21x} = frac{4}{21}$$ So the answer is option A.
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$$frac{ADE}{BDEC} = frac{x}{21x/4} = frac{4x}{21x} = frac{4}{21}$$ So the answer is option A.