1. A shopkeeper purchased 15 kg of variety A rice at X per kg and 10 kg of variety B rice at ‘X+ 5’ per kg. The shopkeeper sold the whole quantity of variety A rice at 10% profit and that of variety B rice at 20% profit. The total selling price of variety A rice was 30/- more than that of variety B rice. Had the two varieties been mixed and sold at an overall profit of 20%, what would have been the selling price of the mixture per kg?
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By: anil on 05 May 2019 01.38 am
Total revenue generated by selling variety A rice = 1.1*15x = 16.50x
Total revenue generated by selling variety B rice = 1.2*10(x+5) = 12x + 60 It is given that, 16.5x - 12x - 60 = 30
$$Rightarrow$$ x = 20.
When the two varieties been mixed and sold at an overall profit of 20%. Total weight of the entire mixture = 10+15 = 25 kg.
Total cost price of the mixture = 15*20 + 10*25 = 550
Therefore, the cost price pf the mixture per kg = dfrac{550}{25} = Rs. 22 per kg.
It is known that the mixture was sold at 20%. Therefore, the selling price of the mixture = 1.2*22 = Rs. 26.40.
Hence, option A is the correct answer.
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Total revenue generated by selling variety B rice = 1.2*10(x+5) = 12x + 60 It is given that, 16.5x - 12x - 60 = 30
$$Rightarrow$$ x = 20.
When the two varieties been mixed and sold at an overall profit of 20%. Total weight of the entire mixture = 10+15 = 25 kg.
Total cost price of the mixture = 15*20 + 10*25 = 550
Therefore, the cost price pf the mixture per kg = dfrac{550}{25} = Rs. 22 per kg.
It is known that the mixture was sold at 20%. Therefore, the selling price of the mixture = 1.2*22 = Rs. 26.40.
Hence, option A is the correct answer.