1. At its usual speed, a train of length L metres crosses platform 300 metre long in 25 seconds. At 50% of its usual speed, the train crosses a vertical pole in 20 seconds. What is the value of L?
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By: anil on 05 May 2019 01.37 am
Let usual speed of the train = $$10x$$ m/s Now, 50% of the speed = $$frac{50}{100} imes 10x = 5x$$ m/s Length of train = $$l$$ m Time taken to cross the pole = 20 sec Using, $$speed = frac{distance}{time}$$ => $$5x = frac{l}{20}$$ => $$x = frac{l}{100}$$ Length of platform = 300 m Acc. to ques, => $$10x = frac{300 + l}{25}$$ => $$10 imes frac{l}{100} = frac{300 + l}{25}$$ => $$frac{l}{10} = frac{300 + l}{25}$$ => $$25l = 3000 + 10l$$ => $$25l - 10l = 15l = 3000$$ => $$l = frac{3000}{15} = 200$$ m
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