1.
In these questions, two equations numbered I and II are given. You have to solve both the equations and select the appropriate option.I. $$3x^{2}-13x+12=0$$
II. $$2y^{2}-15y+28=0$$
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$$(3x-4)(x-3) = 0$$
$$x = frac{4}{3}, 3$$ $$2y^2-15y+28 = 0$$
$$(2y-7)(y-4) = 0$$
$$y = frac{7}{2}, 4$$ x < y