1. A vessel contains a mixture of Grape, Pineapple and Banana juices in the respective ratio of 4 : 6 : 5. 15 litres of this mixture is taken out and 8 litres of grape juice and 2 litres of pineapple juice is added to the vessel. If the resultant quantity of grape juice is 10 litres less than the resultant quantity of pineapple juice. what was the initial quantity of mixture in the vessel ? (in litres)






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  • By: anil on 05 May 2019 01.36 am
    let the amount of grape juice ,pineapple juice and banana juice in vessel be 4y ,6y,5y respectively Now when we removed 15 ltr from vessel the juice will be removed in their given ratio i.e 4 ltr of grape juice will be removed and 6 ltrs of pineapple will be removed and 5 ltrs of banana juice will be removed and hence new quantities are Grape juice = 4y-4 Pineapple juuce = 6y- 6 Banana juice = 5y- 5 Niw 8 ltrs of grape juuce is added and 2 ltrs of pineapple juice is added so new quantities of Juices in vessel are Grape juice = 4y+4 Pineapple juuce = 6y-4 It is given that grape juice amount is 10 ltrs less than pineapple juice quantity . So 6y-4 - 4y-4 = 10 2y= 18 y= 9 Initial quantity in vessel = 15 y = 15×9=135 ltrs
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