1.
Study the given information carefully and answer the questions that follow:
An urn contains 6 red, 4 blue, 2 green, 3 yellow marbles.If four marbles are picked at random what is the probability that at least one is blue ?
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By: anil on 05 May 2019 01.34 am
Total number of events = $$^{15}C_4$$ = 1365
Probability of at least 1 Blue = 1 - (Probability of 0 blue)
Probability of 0 blue = $$frac{^{11}C_4}{1365}$$ = $$frac{22}{91}$$
Probability of at least 1 Blue = 1 - $$frac{22}{91}$$ = $$frac{69}{91}$$
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Probability of at least 1 Blue = 1 - (Probability of 0 blue)
Probability of 0 blue = $$frac{^{11}C_4}{1365}$$ = $$frac{22}{91}$$
Probability of at least 1 Blue = 1 - $$frac{22}{91}$$ = $$frac{69}{91}$$