1. In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 10%
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By: anil on 05 May 2019 01.34 am
Total mixture of sand and iron = 1 kg Quantity of iron = $$frac{20}{100} imes 1 = 0.2$$ kg Let $$x$$ kg of sand should be added, thus total iron in the mixture => $$0.2=frac{10}{100} imes (x+1)$$ => $$2=x+1$$ => $$x=2-1=1$$ kg => Ans - (A)
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