1. 40 30 3600 15 24 17 What is the sum of the two resultant numbers of the set of numbers given above ?






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MCQ-> In each of the following questions two rows of numbers are given. The resultant number in each row is to be worked out separately based on the following rules and the questions below the rows of numbers are to be answered. The operations of numbers progress from left to right. Rules: (a) If an odd number is followed by a two digit even number then they are to be added. (b) If an odd number is followed by a two digit odd number then the second number is to be subtracted from the first number. (c) If an even number is followed by a number which is a perfect square of a number then the second number is to be divided by the first number. (d) If an even number is followed by a two digit even number then he first number is to be multiplied by the second number.15 11 20 400 8 12 10 If the resultant of the second set of a numbers is divided by the resultant of the first set of numbers what will be the outcome ?....
MCQ-> Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET: 1. No one is below the 80th percentile in all 3 sections. 2. 150 are at or above the 80th percentile in exactly two sections. 3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M. 4. Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C: Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.What best can be concluded about the number of candidates sitting for the separate test for BIE who were at or above the 90th percentile overall in CET?
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MCQ->40 30 3600 15 24 17 What is the sum of the two resultant numbers of the set of numbers given above ?....
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