1. Total number of candidates who appeared for CS and ES together in 2011 was 25% more than the total number of candidates who appeared for the same together in 2010. How many female candidates appeared for both the exams together in 2011 if they formed 2/5th of the total number of candidates appearing for both CS and ES exam that year ?
Write Comment
Comments
By: anil on 05 May 2019 01.30 am
Total number of candidates appeared for CS and ES Exam in 2010 =$$ 76,000 + 40,000 = 1,16,000$$
Total number of candidates appeared for CS and ES Exam in 2011 = 1.25 $$ imes$$ Total number of candidates appeared for CS and ES Exam in 2010
= $$ 1.25 imes1,16,000 = frac{5 imes 1,16,000}{4}$$
Total number of female candidates appeared for CS and ES Exam in 2011 = (2/5)th of Total number of candidates appeared for CS and ES Exam in 2011
= $$frac{2}{5} imes frac{5 imes 1,16,000}{4}$$
=$$ frac{1,16,000}{2} = 58,000$$
Option B is the correct answer.
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
Total number of candidates appeared for CS and ES Exam in 2011 = 1.25 $$ imes$$ Total number of candidates appeared for CS and ES Exam in 2010
= $$ 1.25 imes1,16,000 = frac{5 imes 1,16,000}{4}$$
Total number of female candidates appeared for CS and ES Exam in 2011 = (2/5)th of Total number of candidates appeared for CS and ES Exam in 2011
= $$frac{2}{5} imes frac{5 imes 1,16,000}{4}$$
=$$ frac{1,16,000}{2} = 58,000$$
Option B is the correct answer.