1. The height and base of a triangle are equal to the length and breadth of a rectangle respectively. If the perimeter of the rectangle is 86m and the difference between its length and breadth is 5m, what is the area of the triangle ? (in m^{2} )
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By: anil on 05 May 2019 01.21 am
Let length of rectangle = $$x$$ m Breadth = $$(x - 5)$$ m => Perimeter of rectangle = $$2 (x + x - 5) = 86$$ => $$2x - 5 = frac{86}{2} = 43$$ => $$2x = 43 + 5 = 48$$ => $$x = frac{48}{2} = 24$$ => Breadth = 24 - 5 = 19 m => Height of triangle = 24 m and Base of triangle = 19 m $$ herefore$$ Area of triangle = $$frac{1}{2} imes 24 imes 19$$ = $$12 imes 19 = 228 m^2$$
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