1. If two is added to the first three digits and three is subtracted from the last three digits in the number 657489, how many digits in the number thus formed will be multiples of 3 ?
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By: anil on 05 May 2019 01.20 am
Number : 657489 If two is added to the first three digits and three is subtracted from the last three digits, Number = $$(6+2) (5+2) (7+2) (4-3) (8-3) (9-3)$$
= $$879156$$ Thus, only 2 digits are multiples of 3 => Ans - (C)
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= $$879156$$ Thus, only 2 digits are multiples of 3 => Ans - (C)