1. What is the least number that can be added to 3500 to make it a perfect square ?
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By: anil on 05 May 2019 01.19 am
We know that $$60^2 = 3600$$. So, let us calculate $$59^2 = 3481$$
Hence, $$3481 < 3500 < 3600$$ and so, the square which is greater than 3500 and closest to it is 3600. Hence, the least number that must be added to $$3500$$ to make it a perfect square is $$3600-3500 = 100$$
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Hence, $$3481 < 3500 < 3600$$ and so, the square which is greater than 3500 and closest to it is 3600. Hence, the least number that must be added to $$3500$$ to make it a perfect square is $$3600-3500 = 100$$