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The following questions are based on the given information. A man sold 8500 articles in a span of four days. He sold 26% articles on day one. 250/o articles on day 2 and 32% articles on day 3. The remaining articles were sold on day 4.How many articles were sold on day 2 and day 3 together?
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By: anil on 05 May 2019 01.16 am
Articles Sold on day 1 = $$frac{26}{100} imes8500$$ = 2210 Articles Sold on day 2 = $$frac{25}{100} imes8500$$ = 2125 Articles Sold on day 3 = $$frac{32}{100} imes8500$$ = 2720 Total Articles sold in 3 days = 2210 + 2125 + 2720 = 7055 Articles sold on day 2 and day 3 together = 2125 + 2720 = 4845 so the answer is option A
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