1. Dorlin walks certain distance at (5/6)th of the usual speed and takes 16 minutes more than the usual time. Find the usual time taken.
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By: anil on 05 May 2019 01.13 am
Let usual speed = $$6$$ m/min and usual time taken = $$t$$ min => New speed = $$5$$ m/min and new time = $$(t+16)$$ min Also, speed is inversely proportional to time. => $$frac{6}{5}=frac{t+16}{t}$$ => $$6t=5t+80$$ => $$6t-5t=t=80$$ $$ herefore$$ Usual time taken = 1 hr 20 mins => Ans - (D)
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