1. The length of a floor is 125% of its breadth. If the area of floor is $$125m^2$$, what is the sum of the length and the breadth of the floor? (in m)
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By: anil on 05 May 2019 01.12 am
Let breadth of floor = $$x$$ m => Length = $$frac{125}{100} imes x=1.25x$$ m Area = $$x imes1.25x=125$$ => $$x^2=frac{125}{1.25}=100$$ => $$x=sqrt{100}=10$$ $$ herefore$$ Sum of length and breadth = $$x+1.25x=2.25x$$ = $$2.25 imes10=22.5$$ => Ans - (B)
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