1. Dr. Satya Paul Agarwal, recently passed away, was a





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MCQ->Dr. Satya Paul Agarwal, recently passed away, was a....
MCQ->Select the set in which the statements are logically related. A. Mathew and Paul are brothers. B. Siblings are known to quarrel often. C. Mathew and Paul don.t quarrel. D. All those who quarrel are siblings. E. Paul and Mathew quarrel often. F. Mathew and Paul cannot be siblings. ....
MCQ-> Read the data given below and answer the questions based on it. There were 3 sections namely A, B, and C in a test. Out of three sections, 33 students passed in Section A. 34 students passed in Section B and 32 passed in Section C. 10 students passed in Section A and Section B. 9 passed in Section B and Section C, 8 passed in Section A and Section C. The number of students who passed each section alone was equal and was 21 for each section.The ratio of the number of students passed in one or more of the sections to the number of students who passed in Section 7 A alone is:
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MCQ-> Mathematicians are assigned a number called Erdos number (named after the famous mathematician, Paul Erdos). Only Paul Erdos himself has an Erdos number of zero. Any mathematician who has written a research paper with Erdos has an Erdos number of 1.For other mathematicians, the calculation of his/her Erdos number is illustrated below:Suppose that a mathematician X has co-authored papers with several other mathematicians. 'From among them, mathematician Y has the smallest Erdos number. Let the Erdos number of Y be y. Then X has an Erdos number of y+1. Hence any mathematician with no co-authorship chain connected to Erdos has an Erdos number of infinity. :In a seven day long mini-conference organized in memory of Paul Erdos, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Erdos number. Nobody had an Erdos number less than that of F.On the third day of the conference F co-authored a paper jointly with A and C. This reduced the average Erdos number of the group of eight mathematicians to 3. The Erdos numbers of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other co-authorship among any three members would have reduced the average Erdos number of the group of eight to as low as 3.• At the end of the third day, five members of this group had identical Erdos numbers while the other three had Erdos numbers distinct from each other.• On the fifth day, E co-authored a paper with F which reduced the group's average Erdos number by 0.5. The Erdos numbers of the remaining six were unchanged with the writing of this paper.• No other paper was written during the conference.The person having the largest Erdos number at the end of the conference must have had Erdos number (at that time):
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MCQ-> Study the followin information carefully and answer the questions.Four houses Blue, Green, Red and Yellow are located in a row in the given order. Each of the houses is occupied by a person earning a fixed amount of a salary. The four persons are Paul, Krishna, Laxman, and Som.Read the following instruction carefully: I. Paul lives between Som and Krishna II. Laxman does not stay in Blue house III. The person living in Red house earns more than that of person living in Blue IV. Salary of Som is more than that of Paul but lesser than that of Krishna V. One of the person earns Rs. 80, 000 VI. The person earning Rs. 110,000 is not Laxman VII. The salary difference between Laxman and Son is Rs. 30,000 VIII. The House in which Krishna lives is located between houses with persons earning salaries of Rs. 30,000 and Rs. 50,000 IX. Krishna does not live in Yellow house, and the person living in yellow house is not earning lowest salary among the four persons.Who lives in Red house?
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