Toggle navigation
Home
Article Category
Question Papers
General Knowlege
Popular Pages
Multiple Choice Question in 049
Multiple Choice Question in
Multiple Choice Question in 2016
Multiple Choice Question in TRADES-INSTRUCTOR---GR-II---SMITHY---TECHNICAL-EDUCATION
Multiple Choice Question in -current-affairs-2016
Question Answer in ASSISTANT-PROFESSOR---COMPUTER-SCIENCE-AND-ENGINEERING---TECHNICAL-EDUCATION
Multiple Choice Question in ASSISTANT-PROFESSOR---COMPUTER-SCIENCE-AND-ENGINEERING---TECHNICAL-EDUCATION
Multiple Choice Question in english
Multiple Choice Question in abbreviations-abbreviations-m
Multiple Choice Question in SSC CHSL 7 March 2018 Morning Shift
Multiple Choice Question in 072/2016
Question Answer Bank
Multiple Choice Question Bank
Question Answer Category
Multiple Choice Question Category
Home
->
Multiple Choice Questions
1. Heald count in a plain set is
(A): Number of heald eyes per 2 inches across the width
(B): Number of heald eyes per inches across the width
(C): Number of heald eyes per one inch width
(D): Total number of heald eyes present in the heald divided by heald width
Previous Question
Show Answer
Next Question
Add Tags
Report Error
Show Marks
Write Comment
Type in
(Press Ctrl+g to toggle between English and the chosen language)
Post reply
Comments
Tags
Show Similar Question And Answers
QA->What is the name of the new organ which has been discovered hiding in plain sight inside the human body?....
QA->Which plain formed due to the weathering of lime stone?....
QA->Which new alluvial deposits found in the Gangetic plain?....
QA->Who is the author of Plain Speaking ?....
QA->Who is the author of the Plain Speaking ?....
MCQ->What will be the output of the program? class BoolArray { boolean [] b = new boolean[3]; int count = 0; void set(boolean [] x, int i) { x[i] = true; ++count; } public static void main(String [] args) { BoolArray ba = new BoolArray(); ba.set(ba.b, 0); ba.set(ba.b, 2); ba.test(); } void test() { if ( b[0] && b[1] | b[2] ) count++; if ( b[1] && b[(++count - 2)] ) count += 7; System.out.println("count = " + count); } }....
MCQ->Which of the following statements are correct about the C#.NET code snippet given below? namespace IndiabixConsoleApplication { class index { protected int count; public index() { count = 0; } } class index1: index { public void increment() { count = count +1; } } class MyProgram { static void Main(string[] args) { index1 i = new index1(); i.increment(); } } } count should be declared as public if it is to become available in the inheritance chain. count should be declared as protected if it is to become available in the inheritance chain. While constructing an object referred to by i firstly constructor of index class will be called followed by constructor of index1 class. Constructor of index class does not get inherited in index1 class. count should be declared as Friend if it is to become available in the inheritance chain.....
MCQ->What will be the output of the following program? #include<iostream.h> class IndiaBix { static int count; public: static void First(void) { count = 10; } static void Second(int x) { count = count + x; } static void Display(void) { cout<< count << endl; } }; int IndiaBix::count = 0; int main() { IndiaBix :: First(); IndiaBix :: Second(5); IndiaBix :: Display(); return 0; }....
MCQ->Heald count in a plain set is....
MCQ->What will be the output of the following program? #include<iostream.h> class BaseCounter { protected: long int count; public: void CountIt(int x, int y = 10, int z = 20) { count = 0; cout<< x << " " << y << " " << z << endl; } BaseCounter() { count = 0; } BaseCounter(int x) { count = x ; } }; class DerivedCounter: public BaseCounter { public: DerivedCounter() { } DerivedCounter(int x): BaseCounter(x) { } }; int main() { DerivedCounter objDC(30); objDC.CountIt(40, 50); return 0; }....
×
×
Type The Issue
×
Your Marks
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...
Privacy
|
Terms And Conditions