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Multiple Choice Questions
1. I. 2x2-9x+4=0 II y2-14y+40=0
(A): If x=y or the relationship cannot be established.
(B): If x≤y
(C): If x≥y
(D): If x< y
(E): If x >y
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MCQ->Two pairs of straight lines $$x^2 — 7x + 6 = 0$$ and $$y^2 — 14y + 40 = 0$$ intersect to form a rectangle. Let the diagonals of the rectangle intersect at the point W. A circle with center W and with tangents as lines $$y^2 — 14y + 40 = 0$$ intersects lines $$x^2 — 7x + 6 = 0$$ at points P, Q, R, S. The area of the rectangle PQRS is ....
MCQ->I. 2x2-9x+4=0 II y2-14y+40=0....
MCQ->I. $$15x^{2} + 8x + 1 =0$$ II. $$3y^{2} + 14y + 8 = 0$$....
MCQ-> In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and Give answer : I. $$3x^{2} + 20x + 25 = 0$$ II. $$3y^{2} + 14y + 8 =0$$....
MCQ->I. $$4x^{2}-13x+9=0$$ II. $$3y^{2}-14y+16=0$$....
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