1. Which bowler has achieved the feat of double hat tricks in a test match?





Write Comment

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Tags
Show Similar Question And Answers
QA->Who was the first bowler to take 2 hat-tricks during the Cricket World Cup?....
QA->The first Bowler Who Made Hat-Trick In Test Cricket ?....
QA->Who has become the fastest Indian bowler to complete hundred Test wickets during the second match against West Indies at the Wankhede Stadium in Mumbai?....
QA->Who became the first England bowler to take a World Cup hat-trick?....
QA->Who was the first bowler to take a hat-trick in a Cricket World Cup?....
MCQ-> In an innings of a T20 cricket match (a team can bowl for 20 overs) 6 bowlers bowled from the fielding side, with a bowler allowed maximum of 4 overs. Only the three specialist bowlers bowled their full quota of 4 overs each, and the remaining 8 overs were shared among three non-specialist bowlers. The economy rates of four bowlers were 6, 6, 7 and 9 respectively. (Economy rate is the total number of runs conceded by a bowler divided by the number of overs bowled by that bowler). This however, does not include the data of the best bowler (lowest economy rate) and the worst bowler (highest economy rate). The number of overs bowled and the economy rate of any bowler are in integers.Read the two statements below:S1: The worst bowler did not bowl the minimum number of overs. S2: The best bowler is a specialist bowler.Which of the above statements or their combinations can help arrive at the minimum number of overs bowled by a non-specialist bowler?....
MCQ->What will be the output of the following program? #include<iostream.h> double BixFunction(double, double, double = 0, double = 0, double = 0); int main() { double d = 2.3; cout<< BixFunction(d, 7) << " "; cout<< BixFunction(d, 7, 6) << endl; return 0; } double BixFunction(double x, double p, double q, double r, double s) { return p +(q +(r + s x) x) x; }....
MCQ->Which bowler has achieved the feat of double hat tricks in a test match?....
MCQ-> Direction for questions:Given below are six statements followed by sets of three. You are to mark the option in which the statements are most logically related.1. All bricks are tricks 2. Some tricks are shrieks 3. Some that are shrieks are bricks 4. Some tricks are not bricks 5. All tricks are shrieks 6. No tricks are shrieks ....
MCQ-> In the table below is the listing of players, seeded from highest (#1) to lowest (#32), who are due to play in an Association of Tennis Players (ATP) tournament for women. This tournament has four knockout rounds before the final, i.e., first round, second round, quarterfinals, and semi-finals. In the first round, the highest seeded player plays the lowest seeded player (seed # 32) which is designated match No. 1 of first round; the 2nd seeded player plays the 31st seeded player which is designated match No. 2 of the first round, and so on. Thus, for instance, match No. 16 of first round is to be played between 16th seeded player and the 17th seeded player. In the second round, the winner of match No. 1 of first round plays the winner of match No. 16 of first round and is designated match No. 1 of second round. Similarly, the winner of match No. 2 of first round plays the winner of match No. 15 of first round, and is designated match No. 2 of second round. Thus, for instance, match No. 8 of the second round is to be played between the winner of match No. 8 of first round and the winner of match No. 9 of first round. The same pattern is followed for later rounds as well.If there are no upsets (a lower seeded player beating a higher seeded player) in the first round, and only match Nos. 6, 7, and 8 of the second round result in upsets, then who would meet Lindsay Davenport in quarter finals, in case Davenport reaches quarter finals?
 ....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions