1. Who has taken the highest number of wickets in Test Cricket?

Answer: Muttiah Muralitharan

Reply

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Tags
Show Similar Question And Answers
QA->Who has taken the highest number of wickets in Test Cricket?....
QA->How many wickets Kapil Dev had taken in Test matches when he retired?....
QA->The highest number of catches taken by a non-wicketkeeper in an entire Test for India?....
QA->Who has taken maximum wickets in one-day internationals....
QA->Who has taken maximum wickets in one-day internationals?....
MCQ-> Our Glory of Cricket’ club intends to give its membership to a selected few players based on the following criteria The player must be above 16 years and not more than 24 years of age as on 1.2.99. He must pay Rs. 15,000 as entrance fee and Rs. 1,000 as monthly fee throughout his membership period. In case, he pay Rs. 25,000 as additional entrance fee the monthly payment condition is waived. In addition to this he should satisfy at least one of the following conditions : (I) He has won any one inter-college cricket tournament by leading his college team and has scored at least one century in college level tournaments. (II) He has scored at least one century and two fifties in interuniversity of inter state tournaments. (III) He has led his cricket team at college level at least thrice and has taken 10 or more wickets either by bowling or while wicket-keeping or has made aggregate 1000 runs in college level matches. (IV) He has represented his state in national level matches at least thrice with a remarkable bowling or batting or wicket keeping record. (V) He has six centuries at his credit in college level matches and is a spin or medium fast bowler having taken at least one wicket per match in college level matches. Based on the above conditions and the data given in each of the following cases you have to take decision. You are not supposed to assume anything. All the facts are given as on 1.2.99.Ameya started his cricket career exactly 5 years ago by celebrating his 18th birthday by scoring a century. He is ready to pay Rs. 40,000/- at entry level. He scored three fifties representing his state as captain. He is an excellent leg spinner.
 ...
MCQ-> Applicants for the doctoral programmes of Ambi Institute of Engineering (AIE) and Bambi Institute of Engineering (BIE) have to appear for a Common Entrance Test (CET). The test has three sections: Physics (P), Chemistry (C), and Maths (M). Among those appearing for CET, those at or above the 80th percentile in at least two sections, and at or above the 90th percentile overall, are selected for Advanced Entrance Test (AET) conducted by AIE. AET is used by AIE for final selection.For the 200 candidates who are at or above the 90th percentile overall based on CET, the following are known about their performance in CET: 1. No one is below the 80th percentile in all 3 sections. 2. 150 are at or above the 80th percentile in exactly two sections. 3. The number of candidates at or above the 80th percentile only in P is the same as the number of candidates at or above the 80th percentile only in C. The same is the number of candidates at or above the 80th percentile only in M. 4. Number of candidates below 80th percentile in P: Number of candidates below 80th percentile in C: Number of candidates below 80th percentile in M = 4:2:1.BIE uses a different process for selection. If any candidate is appearing in the AET by AIE, BIE considers their AET score for final selection provided the candidate is at or above the 80th percentile in P. Any other candidate at or above the 80th percentile in P in CET, but who is not eligible for the AET, is required to appear in a separate test to be conducted by BIE for being considered for final selection. Altogether, there are 400 candidates this year who are at or above the 80th percentile in P.What best can be concluded about the number of candidates sitting for the separate test for BIE who were at or above the 90th percentile overall in CET?
 ...
MCQ-> Mathematicians are assigned a number called Erdos number (named after the famous mathematician, Paul Erdos). Only Paul Erdos himself has an Erdos number of zero. Any mathematician who has written a research paper with Erdos has an Erdos number of 1.For other mathematicians, the calculation of his/her Erdos number is illustrated below:Suppose that a mathematician X has co-authored papers with several other mathematicians. 'From among them, mathematician Y has the smallest Erdos number. Let the Erdos number of Y be y. Then X has an Erdos number of y+1. Hence any mathematician with no co-authorship chain connected to Erdos has an Erdos number of infinity. :In a seven day long mini-conference organized in memory of Paul Erdos, a close group of eight mathematicians, call them A, B, C, D, E, F, G and H, discussed some research problems. At the beginning of the conference, A was the only participant who had an infinite Erdos number. Nobody had an Erdos number less than that of F.On the third day of the conference F co-authored a paper jointly with A and C. This reduced the average Erdos number of the group of eight mathematicians to 3. The Erdos numbers of B, D, E, G and H remained unchanged with the writing of this paper. Further, no other co-authorship among any three members would have reduced the average Erdos number of the group of eight to as low as 3.• At the end of the third day, five members of this group had identical Erdos numbers while the other three had Erdos numbers distinct from each other.• On the fifth day, E co-authored a paper with F which reduced the group's average Erdos number by 0.5. The Erdos numbers of the remaining six were unchanged with the writing of this paper.• No other paper was written during the conference.The person having the largest Erdos number at the end of the conference must have had Erdos number (at that time):
 ...
MCQ->A cricketer, whose bowling average was 12.4 runs/wicket takes 5 wickets for 22 runs in a match, thereby decreases his average by 0.4. The number of wickets, taken by him before this match was:...
MCQ-> In each of the following questions two rows of number are given. The resultant number in each row is to be worked out separately based on the following rules and the question below the row is to be answered. The operations of number progress from the left to right. Rules: (i) If an even number is followed by another even number they are to be added. (ii) If an even number is followed by a prime number, they are to be multiplied. (iii) If an odd number is followed by an even number, even number is to be subtracted from the odd number. (iv) If an odd number is followed by another odd number the first number is to be added to the square of the second number. (v) If an even number is followed by a composite odd number, the even number is to be divided by odd number.I. 84 21 13 II. 15 11 44 What is half of the sum of the resultants of the two rows ?...
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions