1. The sum of all the natural numbers between 301 and 501 (including 301 and 501) which are divisible by 7 is
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By: anil on 05 May 2019 02.41 am
301 is divisible by 7 (43 times) 497 is also divisible by 7 (71 times) So, the required sum is 7 ( 43 + 44 + .... + 71) = 7 x (sum of numbers upto 71 - sum of numbers upto 42) = 7 * [(71x 72/2)-(42 x 43/2)] = 11571
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