While going down the ball will first cover $$180$$m, then $$frac{180*3}{5}$$, then $$frac{180*3*3}{5*5}$$ and so on.
After rebouncing the ball will cover $$frac{180*3}{5}$$, then $$frac{180*3*3}{5*5}$$ and so on
Thus, there are 2 infinite G.Ps here one of $$180$$, $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,......
and other $$frac{180*3}{5}$$, $$frac{180*3*3}{5*5}$$,.........
Total distance covered by the ball = Distance covered while going up + Distance covered while going down
= $$frac{180}{1-frac{3}{5}} + frac{180*frac{3}{5}}{1-frac{3}{5}}$$ = $$720$$ m.
Hence, option C is the correct answer.