1. The adjoining figure shows a set of concentric squares. If the diagonal of the innermost square is 2 units, and if the distance between the corresponding corners of any two successive squares is 1 unit, find the difference between the areas of the eighth and the seventh squares, counting from the innermost square.
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By: anil on 05 May 2019 02.32 am
Diagonal of 8th square will be = 16
Side of 8th square = $$frac{16}{sqrt2}$$
Diagonal of 7th square will be = 14
Side of 7th square = $$frac{14}{sqrt2}$$
Difference in areas = $$(frac{16}{sqrt2})^2 - (frac{14}{sqrt2})^2$$ = 30
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Side of 8th square = $$frac{16}{sqrt2}$$
Diagonal of 7th square will be = 14
Side of 7th square = $$frac{14}{sqrt2}$$
Difference in areas = $$(frac{16}{sqrt2})^2 - (frac{14}{sqrt2})^2$$ = 30