1. Ujakar and Keshab attempted to solve a quadratic equation. Ujakar made a mistake in writing down the constant term. He ended up with the roots (4, 3). Keshab made a mistake in writing down the coefficient of x. He got the roots as (3, 2). What will be the exact roots of the original quadratic equation?
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By: anil on 05 May 2019 02.31 am
We know that quadratic equation can be written as $$x^2$$-(sum of roots)*x+(product of the roots)=0.
Ujakar ended up with the roots (4, 3) so the equation is $$x^2$$-(7)*x+(12)=0 where the constant term is wrong.
Keshab got the roots as (3, 2) so the equation is $$x^2$$-(5)*x+(6)=0 where the coefficient of x is wrong . So the correct equation is $$x^2$$-(7)*x+(6)=0. The roots of above equations are (6,1).
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Ujakar ended up with the roots (4, 3) so the equation is $$x^2$$-(7)*x+(12)=0 where the constant term is wrong.
Keshab got the roots as (3, 2) so the equation is $$x^2$$-(5)*x+(6)=0 where the coefficient of x is wrong . So the correct equation is $$x^2$$-(7)*x+(6)=0. The roots of above equations are (6,1).