1. Three runners A, B and C run a race, with runner A finishing 12 m ahead of runner B and 18 m ahead of runner C, while runner B finishes 8 m ahead of runner C. Each runner travels the entire distance at a constant speed. What was the length of the race?
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- By: anil on 05 May 2019 02.31 amLet x be the required distance. Let a,b,c be speed of the A,B and C respectively. From the given conditions we have, $$frac{a}{b}=frac{x}{x-12}$$ and $$frac{a}{c}=frac{x}{x-18}$$ and $$frac{b}{c}=frac{x}{x-8}$$ . From first 2 equations we can deduce $$frac{b}{c}=frac{x-12}{x-18}$$. $$frac{b}{c}=frac{x-12}{x-18} = frac{x}{x-8}$$ x = 48 satisfy the equation.
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