Three pieces of cakes of weights 4.5 lb, 6.75 lb and 7.2 lb respectively are to be divided into parts of equal weight. Further, each part must be as heavy as possible. If one such part is served to each guest, then what is the maximum number of guest ?->(Show Answer!)

1. Three pieces of cakes of weights 4.5 lb, 6.75 lb and 7.2 lb respectively are to be divided into parts of equal weight. Further, each part must be as heavy as possible. If one such part is served to each guest, then what is the maximum number of guests that could be entertained?

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By: anil on 05 May 2019 02.30 am

HCF of [(9/2), (27/4), (36/5)] = HCF of numerators / LCM of denominators = 9/20 Total weight = 18.45 lb So no. of parts = 18.45 / (9/20) = 18.45*20/9 = 41 Hence option d) is the correct answer.

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