1. If 7 (110) 4 and 19 (930), 12, then what is the value of ‘A’ in 16 (A) 9 ?
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By: anil on 05 May 2019 02.27 am
The pattern followed is that for the numbers : $$x(z)y$$, $$z=(x+y) imes(x+y-1)$$ Eg :- 7 (110) 4 => Here $$7+4=11equiv(11 imes10)=110$$ and 19 (930) 12 => Here $$19+12=31equiv(31 imes30)=930$$ Similarly, 16 (A) 9 => Here $$16+9=25$$ => $$A=25 imes24=600$$ => Ans - (B)
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