1. If diagonals of a rhombus are 12 cm and 16 cm, then what is the perimeter (in cm) of the rhombus?
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By: anil on 05 May 2019 02.25 am
Two diagonals of the rhombus are 12 cms and 16 cms (Given) We know that, The sides of the rhombus are congruent i.e sides have same length and
Two diagonals are perpendicular and bisect each other. $$ herefore angle AOB = 90^{circ}$$ and AB = $$sqrt{6^{2} + 8^{2}} = sqrt{36 + 64} = sqrt{100} = 10$$ Now, perimeter = $$4(10) = 40$$ Hence, option B is the correct answer.
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Two diagonals are perpendicular and bisect each other. $$ herefore angle AOB = 90^{circ}$$ and AB = $$sqrt{6^{2} + 8^{2}} = sqrt{36 + 64} = sqrt{100} = 10$$ Now, perimeter = $$4(10) = 40$$ Hence, option B is the correct answer.