1. If two concentric circles are of radii 5 cm and 3 cm, then the length of the chord of the larger circle which touches the smaller circle is





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  • By: anil on 05 May 2019 02.22 am
    Given : $$C_1$$ and $$C_2$$ be the two concentric circles having radius $$r_1=3$$ cm and $$r_2=5$$ cm respectively. To find : AB = ? Solution : AB is the the tangent to the circle $$C_1$$, hence $$angle$$ OPB = $$90^circ$$ Also, the perpendicular from the centre of a circle to a chord bisects the chord. Thus, in $$ riangle$$ OPB, => $$(PB)^2=(OB)^2-(OP)^2$$ => $$(PB)^2=(5)^2-(3)^2$$
    => $$(PB)^2=25-9=16$$ => $$PB=sqrt{16}=4$$ cm $$ herefore$$ AB = $$2 imes4=8$$ cm => Ans - (D)
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