All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm. BC = 7.5 cm. CD = 3 cm, then DA is ?->(Show Answer!)

1. All sides of a quadrilateral ABCD touch a circle. If AB = 6 cm. BC = 7.5 cm. CD = 3 cm, then DA is

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By: anil on 05 May 2019 02.22 am

Given : AB = 6 cm. BC = 7.5 cm. CD = 3 cm To find : DA = ? Solution : Tangents from the same point to a circle are equal in length. => $$AE=AH$$, $$BE=BF$$, $$CG=CF$$ and $$DG=DH$$ Adding above equations, we get : => $$(AE+BE)+(CG+DG)=(BF+CF)+(AH+DH)$$ => $$AB+CD=BC+DA$$ => $$6+3=7.5+DA$$ => $$DA=9-7.5=1.5$$ cm => Ans - (D)

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