1. A man bought some eggs of which 10% are rotten. He gives 80% of the remainder of his reighbours. Now he is left out with 36 eggs. How many eggs he bought?
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By: anil on 05 May 2019 02.19 am
Let the man bought $$100x$$ eggs Eggs left after removing the rotten ones = $$100x-(frac{10}{100} imes100x)=90x$$ Eggs given to neighbours = $$frac{80}{100} imes90x=72x$$ Thus, eggs remaining = $$90x-72x=36$$ => $$18x=36$$ => $$x=frac{36}{18}=2$$ $$ herefore$$ Number of eggs bought = $$2 imes100=200$$ => Ans - (D)
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