1. What is the total surface area (in sq cm) of a hollow cylinder open at both ends, if its length is 22 cm, external radius is 7 cm and thickness is 1 cm? (Take π = 22/7)
Write Comment
Comments
By: anil on 05 May 2019 02.17 am
Let the external radius, the internal radius and the height of the hollow cylinder be R, r and h respectively. => R = 7 cm , h = 22 cm and r = 7 - 1 = 6 cm Total surface area of hollow cylinder = $$(2 pi R h) + (2 pi r h) + 2 pi(R^2 - r^2)$$ = $$(2 imes frac{22}{7})[(7 imes 22) + (6 imes 22) + (7^2 - 6^2)]$$ = $$(frac{44}{7}) imes (154 + 132 + 13)$$ = $$frac{44}{7} imes 299 = 1879.428 approx 1879.43$$ $$cm^2$$ => Ans - (A)
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use