Radius of cone = Radius of cylinder = r = 5 m Height of cylinder = h = 6 m Slant height of cone = l = 10 m Canvas required = Curved surface area of cylinder + Curved surface area of cone = $$2 pi r h + pi r l = (pi r) (2 h + l)$$ = $$(frac{22}{7} imes 5) (2 imes 6 + 10)$$ = $$frac{110}{7} imes 22 = 345.71$$ $$m^2$$ Also, 20% extra canvas is required for folding and stitching $$ herefore$$ Total canvas required = $$frac{120}{100} imes 345.71$$ = $$1.2 imes 345.71 approx 414.86$$ $$m^2$$ => Ans - (B)