1. The cross section of a canal is in the shape of an isosceles trapezium which is 4 m wide at the bottom and 5 m wide at the top. If the depth of the canal is 2 m and it is 120 m long, what is the maximum capacity of this canal?
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By: anil on 05 May 2019 02.14 am
The canal is 4 m wide at the bottom and 5 m at the top, thus the canal is in the shape of a trapezium whose volume will be equal to the product of area of trapezium and the width. Length of canal = 120 m Volume of canal = $$(frac{1}{2} imes $$(sum of parallel sides) $$ imes$$ height $$) imes$$ length => Volume = $$(frac{1}{2} imes (5+4) imes 2) imes 120$$ = $$9 imes 120 = 1080$$ $$m^3$$ => Ans - (D)
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