1. The total cost of a stove with cooker was Rs 13,125. The cooker was sold at a profit of 30% and the stove at a loss of 20%. If the sale price was the same in both the items, then the cost price of the cheaper item was
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By: anil on 05 May 2019 02.13 am
Let cost price of stove = $$Rs. 100x$$ => Cost price of cooker = $$Rs. (13,125 - 100x)$$ Selling price of cooker (30% profit) = Selling price of stove (20% loss) => $$frac{130}{100} imes (13,125 - 100x) = frac{80}{100} imes 100x$$ => $$17062.5 - 130x = 80x$$ => $$x = frac{17062.5}{210} = 81.25$$ => Cost price of stove = $$100 imes 81.25 = Rs. 8,125$$ => Cost price of cooker = $$13,125 - 8,125 = Rs. 5,000$$ $$ herefore$$ Cooker is cheaper with cost price = Rs. 5,000
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