Two cars travel from city A to city B at a speed of 36 and 48 km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is ?->(Show Answer!)

1. Two cars travel from city A to city B at a speed of 36 and 48 km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is

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By: anil on 05 May 2019 02.08 am

Let the distance between City A and City B = $$d$$ km Speed of first car = 36 km/hr and speed of second car = 48 km/hr Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3)$$ hrs Using, speed = distance/time for first car : => $$frac{d}{t} = 36$$ => $$d = 36t$$ --------------(i) For second car, => $$frac{d}{t - 3} = 48$$ Substituting value of $$d$$ from equation (i), we get : => $$36t = 48t - 144$$ => $$48t - 36t = 12t = 144$$ => $$t = frac{144}{12} = 12$$ hrs From equation (i), => $$d = 36 imes 12 = 432$$ km => Ans - (B)

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