1. In ΔUVW measure of angle V is 90°. If cosecU = 13/12, and UV = 2.5cm, then what is the length (in cm) of side VW?
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By: anil on 05 May 2019 02.06 am
Given : $$cosec U$$ = $$frac{13}{12}$$ Also, $$cosec U=frac{UW}{VW}=frac{13}{12}$$ Let UW = $$13x$$ cm and VW = $$12x$$ cm Thus, in $$ riangle$$ UVW, => $$(UV)^2=(UW)^2-(VW)^2$$ => $$(UV)^2=(13X)^2-(12X)^2$$ => $$(UV)^2=169x^2-144x^2=25x^2$$ => $$UV=sqrt{25x^2}=5x$$ cm According to ques, => $$5x=2.5$$ => $$x=frac{2.5}{5}=frac{1}{2}$$ $$ herefore$$ VW = $$12 imesfrac{1}{2}=6$$ cm => Ans - (B)
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